How do you find the exact value of #sec30cot45#?

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Answer 1 · 2018-06-20T19:33:49

#(2sqrt3)/3#

#=sec30cot45#

#=1/cos30*1/tan45#

use the unit circle to find exact values:

#cos30=sqrt3/2#

#1/cos30=2/sqrt3#

#tan45=1#

#1/tan45=1/1=1#

#=sec30cot45 = 2/sqrt3*1=2/sqrt3=(2sqrt3)/3#

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