Question

How do you find the LCM of `d+2, (d-2)^2`, and `d^2-4`?

Answer 1

`(d+2)(d-2)^2`

Explanation:

`d^2 - 4 = (d - 2)(d +2)`

The irreductibles are `d+2` and `d-2`

And their higher exponents are `1` and `2` respectively.

Aditionally, their lower exponents are 0.

`gcd(p, q, r) = 1`