How do you solve this system of inequalities: $7 x + 2 y < - 2 and - 4 x + 3 y \geq 3$ $7x + 2y < - 2 and - 4x + 3y \geq 3$ ?

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How do you solve this system of inequalities: $7 x + 2 y < - 2 and - 4 x + 3 y \geq 3$ $7x + 2y < - 2 and - 4x + 3y \geq 3$ ?

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Answer 1 · 2018-06-21T06:48:29

Graph each inequality separately, the overlap of the shaded areas is your solution.

Explanation:

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Solve each equation for y , $y < 2 x + 3$ $y<2x+3$ for example, then graph each one. Test a point in each equation to find which side of each inequality to shade.

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How do you solve this system of inequalities: $7 x + 2 y < - 2 and - 4 x + 3 y \geq 3$ $7x + 2y < - 2 and - 4x + 3y \geq 3$ ?

1 Answer

Explanation:

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How do you solve this system of inequalities: 7x + 2y < - 2 and - 4x + 3y \geq 37x+2y<−2and−4x+3y≥37x + 2y < - 2 and - 4x + 3y \geq 3?

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Explanation:

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How do you solve this system of inequalities: $7 x + 2 y < - 2 and - 4 x + 3 y \geq 3$ $7x + 2y < - 2 and - 4x + 3y \geq 3$ ?