How do you divide $\frac{x^{2} + 2 x - 24}{20 - 5 x} + \frac{x^{2} + 4 x - 12}{2 x + 4}$ $\frac { x ^ { 2} + 2x - 24} { 20- 5x } + \frac { x ^ { 2} + 4x - 12} { 2x + 4}$ ?

Question

1166 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-06-22T04:17:32

$\frac{3 x^{2} + 4 x - 84}{10 x + 20}$ $(3x^2+4x-84)/(10x+20)$

$\frac{x . (x + 6) - 4 (x + 6)}{- 5 (x - 4)} + \frac{x^{2} + 4 x - 12}{2 x + 4}$ $(x.(x+6)-4(x+6))/(-5(x-4))+(x^2+4x-12)/(2x+4)$

$\frac{(x - 4) (x + 6)}{- 5 (- 4)} + \frac{x^{2} + 4 x - 12}{2 x + 4}$ $((x-4)(x+6))/(-5(-4))+(x^2+4x-12)/(2x+4)$

$\frac{x + 6}{- 5} + \frac{x^{2} + 4 x - 12}{2 x + 4}$ $(x+6)/(-5)+(x^2+4x-12)/(2x+4)$

$- \frac{x + 6}{5} + \frac{x^{2} + 4 x - 12}{2 x + 4}$ $-(x+6)/(5)+(x^2+4x-12)/(2x+4)$

$\frac{- 2 (2 x + 4) (x + 6) + 5 (x^{2} + 4 x - 12)}{5 (2 x + 4)}$ $(-2(2x+4)(x+6)+5(x^2+4x-12))/(5(2x+4))$

$\frac{- (2 x^{2} + 12 x + 4 x + 24) + 5 x^{2} + 20 x - 60}{10 x + 20}$ $(-(2x^2+12x+4x+24)+5x^2+20x-60)/(10x+20)$

$\frac{- 2 x^{2} - 16 x - 24 + 5 x^{2} + 20 x - 60}{10 x + 20}$ $(-2x^2-16x-24+5x^2+20x-60)/(10x+20)$

$\frac{3 x^{2} + 4 x - 84}{10 x + 20}$ $(3x^2+4x-84)/(10x+20)$

How do you divide \frac { x ^ { 2} + 2x - 24} { 20- 5x } + \frac { x ^ { 2} + 4x - 12} { 2x + 4}x2+2x−2420−5x+x2+4x−122x+4\frac { x ^ { 2} + 2x - 24} { 20- 5x } + \frac { x ^ { 2} + 4x - 12} { 2x + 4}?