How do you combine like terms in $2 n^{3} (4 n^{4} - 5 n^{2} - 6) - 4 n^{3} (6 n^{2} + n^{4} - 7)$ $2n ^ { 3} ( 4n ^ { 4} - 5n ^ { 2} - 6) - 4n ^ { 3} ( 6n ^ { 2} + n ^ { 4} - 7)$ ?

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Answer 1 · 2018-06-22T07:09:43

$2 n^{3} \cdot (n^{2} - 8) \cdot (2 n^{2} - 1)$ $2n^3*(n^2-8)*(2n^2-1)$

$2 n^{3} \cdot (4 n^{4} - 5 n^{2} - 6 - 2 (6 n^{2} + n^{4} - 7)$ $2n^3*(4n^4-5n^2-6-2(6n^2+n^4-7)$

$2 n^{3} \cdot (4 n^{4} - 5 n^{2} - 6 - 12 n^{2} - 2 n^{4} + 14)$ $2n^3*(4n^4-5n^2-6-12n^2-2n^4+14)$

$2 n^{3} \cdot (2 n^{4} - 17 n^{2} + 8)$ $2n^3*(2n^4-17n^2+8)$

$2 n^{3} \cdot (n^{2} \cdot (2 n^{2} - 1) - 8 (2 n^{2} - 1))$ $2n^3*(n^2*(2n^2-1)-8(2n^2-1))$

How do you combine like terms in 2n3(4n4−5n2−6)−4n3(6n2+n4−7)2n ^ { 3} ( 4n ^ { 4} - 5n ^ { 2} - 6) - 4n ^ { 3} ( 6n ^ { 2} + n ^ { 4} - 7)?