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How do you solve $8 r - r^{2} \geq 15$ $8r-r^2>=15$ ?

1 Answer

Jun 22, 2018

$r \in [3, 5]$ $rin[3,5]$

Explanation:

$8 r - r^{2} - 15 \geq 0$ $8r-r^2-15>=0$

$- r^{2} + 8 r - 15 \geq 0$ $-r^2+8r-15>=0$

$- r + 5 r + 3 r - 15 \geq 0$ $-r+5r+3r-15>=0$

$- r \cdot (r - 5) + 3 (r - 5) \geq 0$ $-r*(r-5)+3(r-5)>=0$

$(- r + 3) \cdot (r - 5) \geq 0$ $(-r+3)*(r-5)>=0$

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