How do you solve $7^ { x } - 7^ { x + 1} \leq - 6$ ?

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Answer 1 · 2018-06-22T09:09:40

$x>=log_7(55)-1$

$49-7^(x+1)<=-6$

$-7^(x+1)<=-6-49$

$-7^(x+1)<=-55$

$7^(x+1)>=55$

$x-1>=log_7(55)$

How do you solve 7^ { x } - 7^ { x + 1} \leq - 67^ { x } - 7^ { x + 1} \leq - 6?