What is the axis of symmetry and vertex for the graph #y= x^2+ 5x - 12#?

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Answer 1 · 2018-06-22T14:10:08

#aos = (-5)/2#

vertex: #(-5/2,-73/4)#

In the form:

#y=ax^2+bx+c#

the axis of symmetry is:

#aos = (-b)/2#

#y= x^2+ 5x - 12#

#aos = (-5)/2#

The vertex is: #(aos, f(aos)) = (-5/2,(f(-5/2))#

#y= (-5/2)^2+ 5(-5/2) - 12=-73/4#

vertex: #(-5/2,-73/4)#

graph{y= x^2+ 5x - 12 [-20.25, 19.75, -21.44, -1.44]}