What is the growth factor, initial amount for M(t)=8(2)^(1/6t)?

1 Answer
Jun 22, 2018

Growth factor = 2
Initial Amount = 8

Explanation:

You're using the form A(t)=A_0(b)^(t/k), where:
A_0 = the initial amount
b = the growth factor
t = the amount of time elapsed
k = the amount of time it takes to double/triple/etc.

Note: M(t) and A(t) are the same, just using different variables.

Your equation represents a doubling in whatever the problem applies to. It takes 6 years to double. In order to avoid confusion, you can place the t in the fraction in the exponent:

M(t)=8(2)^(t/6)