Question

How do you differentiate `g(y) =(2x-5 )e^x` using the product rule?

Answer 1

`(2x-5)e^x+2e^x`

Explanation:

product rule states that: `d/dx(u(x)*v(x))=u'(x)*v(x)+u(x)v'(x)`
in your case `u(x)=(2x-5)`
and `v(x)=e^x`
thereby `u'(x)=2` and `v'(x)=e^x`