Let x > 0, prove x^2 + 1 > lnx?
2 Answers
Two cases:
For
For
For all
We've shown both cases, so this is true for all
As
Explanation:
For any number
As
Graphically it is quite clear:
Two cases:
For
For
For all
We've shown both cases, so this is true for all
As
For any number
As
Graphically it is quite clear: