How do you solve #|x+45| = -6#?
1 Answer
Jun 22, 2018
Explanation:
we have
now we have two cases
- Case 1(
#(x+45)>=0;x>=-45# ........(a)
#(x+45)=-6#
#x=-6-45; x=-51# .........(b)
from (a) and (b) we get
#x in phi# - Case 2(
#(x+45)<0;x<-45# ......(d)
#-(x+45)=-6# ........(a negative sign is there because for any value of x<-45,(|A|), A will be negative)
now we get#x=-39# ..............(e)
Again from (d)and (e)
# x in phi#
hence there is no real solution for x
i.e.#x in phi#