What are the asymptotes and removable discontinuities, if any, of f(x)=(2x^3)/(x+1) ?

1 Answer
Jun 22, 2018

vertical asymptote at x=-1
no removable discontinuities.

Explanation:

Just set the denominator equal to zero in this case:
x+1=0
which solves for
x=-1
since the highest exponent in the nummerator is higher this is a pole and doesnt cancel out.