How do you solve x-y<-1?

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Answer 1 · 2018-06-22T23:44:02

See solution process below;

$x - y < - 1$ $x - y < -1$

Solving for $x$ $x$

$x - y < - 1$ $x - y < - 1$

Add $y$ $y$ to both sides;

$x - y + y < - 1 + y$ $x - y + y < - 1 + y$

$x + 0 < - 1 + y$ $x + 0 < - 1 + y$

$x < - 1 + y$ $x < -1 + y$

$x < y - 1$ $x < y - 1$

Similarly..

Solving for $y$ $y$

$x - y < - 1$ $x - y < - 1$

Subtract $x$ $x$ from both sides;

$x - y - x < - 1 - x$ $x - y - x < - 1 - x$

$x - x - y < - 1 - x$ $x - x - y < - 1 - x$

$0 - y < - 1 - x$ $0 - y < - 1 - x$

$- y < - 1 - x$ $-y < - 1 - x$

Multiplying through by minus, the inequality sign would change in the opposite direction..

$y > 1 + x$ $y > 1 + x$

$y > x + 1$ $y > x + 1$