Question

Find the real zeros (if any) of the polynomial ?

Answer 1

`x=0` and `x=-8`

Explanation:

At least `y=0` when `x=0`, since `x=0` gives `ax^5=0` for any a.

Other than that you will have to have `x^6+9=0`, i.e.

`x^6=-9`
This has a complex solution (`x=(-9)^(1/6)` (the 6th root of -9),
which would not be a real zero.

My answer, therefore, would be `x=0` and `x=-8`