Question

How do you multiply `3x ^ { 2} y ( 2x ^ { 2} + 7x y - 6y ^ { 2} )`?

Answer 1

`6x^4y+21x^³y^²-18x^²y^³`

Explanation:

We can use the distributive property here. Whenever multiplying numbers with bases, we multiply the coefficients (the numbers before the bases, which in this case are x and y) and add the exponents.

So first distribute `3x^²y` to each term inside the parentheses.
`(3x^²y) · (2x^²)= 6x^4y` ,etc.

We end up with:
`6x^4y+21x^³y^²-18x^²y^³`