How do you solve #x^2-2x-8=0# by graphing?
1 Answer
We need to find the vertex, x-intercepts, and y-intercept to give us an idea of what the graph will look like.
Explanation:
Let's find the vertex first. We can find the x-coordinate by using
The y-coordinate can be found by plugging the x-value back into the equation:
The vertex is
The x-intercepts are
The y-intercept is
graph{x^2-2x-8 [-9, 11, -10, 1]}