Question

If I want heat 60degrees the 30liters of within 5mins, how much wattage is required..??

Answer 1

P= 25,12 kW

Explanation:

the amount of heat is ( i suppose water where 1 kg= 1 L):
`Q = m xx Cp xx Delta T= 30 kg xx 1( Kcal)/(kg xx K) xx 60°C=1800 kcal = 7.536 xx 10^6 J=`
i remember that 1 Kcal = 4186 J
Power is the energy diveded by time (5 min = 300 s)
`P= E/t=(7.536 xx 10^6 J)/(300s)= 2,512 xx 10^4 W = 25,12 kW`