(ln^2 x)/x integral from 1 to e^2 is?
#int_1^(e^2)ln^2x/xdx# =?
2 Answers
Jun 24, 2018
Explanation:
We want to evaluate
#I=int_1^(e^2)ln^2(x)/xdx#
Make a substitution
New limits
#I=int_0^2 u^2/x*xdu=int_0^2 u^2du=1/3[u^3]_0^2=8/3#
Jun 24, 2018
Explanation:
to integrate
substitute
plugging this in will give:
and we will get: