A charge of 7 C is at the origin. How much energy would be applied to or released from a 9 C charge if it is moved from (2 ,-2 ) to (2 ,-1 ) ?

1 Answer
Jun 24, 2018

335.66 * 10^9 J of energy is relesed

Explanation:

As energy is scalar, only the distance of charges from origin are considered.

U_i = 1/(4piepsilon_0) (7*9)/sqrt8

and

U_f = 1/(4piepsilon_0) (7*9)/sqrt5

"Work done by external force" = U_f - U_i

rArr"Work done by external force" = 1/(4piepsilon_0) (7*9)/sqrt5 - 1/(4piepsilon_0) (7*9)/sqrt8

rArr"Work done by external force"="Energy released/gained"= -335.66 * 10^9 J

As work done is negetive, energy is released.