How many atoms of carbon has a young man has given to his bride to be if the engagement ring contains 0.5 carat diamond? There are 200mg in a cara.

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How many atoms of carbon has a young man has given to his bride to be if the engagement ring contains 0.5 carat diamond? There are 200mg in a cara.

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Answer 1 · 2018-06-24T18:17:26

$5.02 \times 10^{21} atoms$ $5.02xx10^21 " atoms"$

Explanation:

First, we'll work out the mass of the diamond.

$mass = 200 \times 10^{- 3} \times 0.5$ $"mass"=200xx10^-3xx0.5$

$= 0.1 g$ $=0.1"g"$

Now, we can find the number of moles of carbon in 0.1g.

$mass = M_{r} \times moles$ $"mass"=M_rxx"moles"$

$moles = \frac{mass}{M_{r}}$ $"moles"="mass"/M_r$

$= \frac{0.1}{12}$ $=0.1/12$

$= \frac{1}{120} = 8.33 \times 10^{- 3} mol$ $=1/120=8.33xx10^-3 "mol"$

To find the number of carbon atoms, we multiply this by Avogadro's number, $6.02 \times 10^{23}$ $6.02xx10^23$

$number of atoms = \frac{1}{120} \times 6.02 \times 10^{23}$ $"number of atoms"=1/120xx6.02xx10^23$

$= 5.02 \times 10^{21} atoms$ $=5.02xx10^21 " atoms"$ (3sf)

Answer 2 · 2018-06-24T18:22:47

$n = .5 \ "carat" times {200 \ "mg"}/{"carat"} times {1\ "gram"}/{1000\ "mg"} times {1\ "mole"}/{12.01\ "gram"} times { 6.02 times 10^{23} \ "atoms"}/{"mole"} = 5.01 times 10^21 \ "atoms"$

Explanation:

I haven't done a chemistry question in forty years. I used $12.01$ as the atomic weight of carbon, assuming it's a mixture of isotopes. $6.02 times 10^23$ is of course Avogadro's constant giving molecules per mole.

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How many atoms of carbon has a young man has given to his bride to be if the engagement ring contains 0.5 carat diamond? There are 200mg in a cara.

2 Answers

Explanation:

Explanation:

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