How do you factor completely #8x^3-20x^2+6x-15#? Algebra Polynomials and Factoring Factoring Completely 1 Answer Nghi N. Jun 24, 2018 #f(x) = (4x^2 + 3)(2x - 5)# Explanation: Factor by grouping: #f(x) = 8x^3 - 20x^2 + 6x - 15# #f(x) = 8x^3 + 6x - 20x^2 - 15# #f(x) = 2x(4x^2 + 3) - 5(4x^2 + 3)# #f(x) = (4x^2 + 3)(2x - 5)# Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely #2x^2-8#? Which method do you use to factor #3x(x-1)+4(x-1) #? What are the factors of #12x^3+12x^2+3x#? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor #12c^2-75# completely? How do you factor #x^6-26x^3-27#? How do you factor #100x^2+180x+81#? See all questions in Factoring Completely Impact of this question 1664 views around the world You can reuse this answer Creative Commons License