How do you write an equation for a line with m=3.5 and #f(-2)=1#? Algebra Forms of Linear Equations Write a Function in Slope-Intercept Form 1 Answer Patrick H. Jun 25, 2018 #f(-2)=1# means that a point exists at #(-2,1)#. Using our formula for the slope-intercept form of a line, #y=mx+b#, we can just plug in values and find the equation: #1=3.5(-2)+b# #1=-7+b# #8=b# #y=3.5x+8# or #y=7/2 x+8# Answer link Related questions How do you determine the #(x,y)# point given #f(x)=y#? How do you evaluate functions? What are the two points if you are given #f(-1)=2# and #f(0)=-6#? How do you write an equation for a line given #f(-1)=1# and #f(1)=-1#? How do you write an equation for a line given #m=-7# and #f(2)=-1#? How do you determine the slope given #f(-4)=2# and #f(0)=3#? How do you write an equation of the line with slope -3 and y-intercept (0,-5)? How do you find the slope-intercept form of the equation of the line that passes through (-2,... How do you write the slope intercept form of the equation of the line through the given point... Given the equation y - 3 =1/2 (x=6) in point-slope form, how do you identify the equation of the... See all questions in Write a Function in Slope-Intercept Form Impact of this question 3468 views around the world You can reuse this answer Creative Commons License