How do you solve #2x^2+x<15#? Precalculus Solving Rational Inequalities Polynomial Inequalities 1 Answer Brandon Jun 25, 2018 #-3 < x <2.5# Explanation: We can re-arrange and say: #2x^2+x-15<0# By factorising: #(2x-5)(x+3)<0# #therefore# #2x-5<0# #rArr 2x<5# #rArr x<2.5# #x+3<0# #rArr x<-3# Therefore: #therefore# #-3 < x <2.5# Answer link Related questions What are common mistakes students make when solving polynomial inequalities? How do I solve a polynomial inequality? How do I solve the polynomial inequality #-2(m-3)<5(m+1)-12#? How do I solve the polynomial inequality #-6<=2(x-5)<7#? How do I solve the polynomial inequality #1<2x+3<11#? How do I solve the polynomial inequality #-12<-2(x+1)<=18#? How do you solve the inequality #6x^2-5x>6#? How do you solve #x^2 - 4x - 21<=0# A) [-3, 7] B) (-∞, -3] C) (-∞, -3] [7, ∞) D) [7, ∞)? How do you solve quadratic inequality, graph, and write in interval notation #x^2 - 8x + 15 >0#? How do you solve #-x^2 - x + 6 < 0#? See all questions in Polynomial Inequalities Impact of this question 2929 views around the world You can reuse this answer Creative Commons License