How do you factor #216 - x^3#? Algebra Polynomials and Factoring Factoring Completely 1 Answer IZUkuABA Jun 25, 2018 #(6-x)*(36+6x+x^2)# Explanation: We have #216-x^3# Now #6^3=216# Then we get #6^3-x^3# Using #a^3-b^3=(a-b)*(a^2+a*b+b^2)# We get #(6-x)*(36+6x+x^2)# Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely #2x^2-8#? Which method do you use to factor #3x(x-1)+4(x-1) #? What are the factors of #12x^3+12x^2+3x#? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor #12c^2-75# completely? How do you factor #x^6-26x^3-27#? How do you factor #100x^2+180x+81#? See all questions in Factoring Completely Impact of this question 3442 views around the world You can reuse this answer Creative Commons License