How do you solve the inequality $7 + 2 p < - 14$ $7 + 2p< -14$ ?

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Answer 1 · 2018-06-26T12:48:07

$p < - \frac{21}{2}$ $p < - 21/2$

$7 + 2 p < - 14$ $7 + 2p < - 14$

Subtracting $7$ $7$ from both sides;

$7 + 2 p - 7 < - 14 - 7$ $7 + 2p - 7 < - 14 - 7$

$7 - 7 + 2 p < - 21$ $7 - 7 + 2p < - 21$

$0 + 2 p < - 21$ $0 + 2p < - 21$

$2 p < - 21$ $2p < - 21$

Dividing both sides by the coefficient of $p$ $p$

$\frac{2 p}{2} < - \frac{21}{2}$ $(2p)/2 < - 21/2$

$(cancel2p)/cancel2 < - 21/2$

$p < - 21/2$

Answer 2 · 2018-07-05T22:36:00

$p<-21/2$

Recall that we want to isolate $p$ . We can start by subtracting $7$ from both sides to get

$2p<-21$

Dividing both sides by $2$ gives us

$p<-21/2$

Hope this helps!

How do you solve the inequality 7 + 2p< -147+2p<−147 + 2p< -14?