If f(x)=x+4 and g(x)= x^2-1 , what is (g*f)(x)?

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If f(x)=x+4 and g(x)= x^2-1 , what is (g*f)(x)?

$f (x) = x^{2} - 2 and g (x) = x - 3$ $f(x)=x^2-2 and g(x)= x-3$
$(g \circ f) (x)$ $(g@f)(x)$

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Answer 1 · 2018-06-26T15:09:09

$(g \circ f) (x) = x^{2} - 5$ $(g@f)(x)=x^2-5$

Explanation:

$(g \circ f) (x) = g (f (x))$ $(g@f)(x)=g(f(x))$
$(g \circ f) (x) = (x^{2} - 2) - 3$ $(g@f)(x)=(x^2-2)-3$
$(g \circ f) (x) = x^{2} - 5$ $(g@f)(x)=x^2-5$

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If f(x)=x+4 and g(x)= x^2-1 , what is (g*f)(x)?

$f (x) = x^{2} - 2 and g (x) = x - 3$ $f(x)=x^2-2 and g(x)= x-3$
$(g \circ f) (x)$ $(g@f)(x)$

1 Answer

Explanation:

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Math

Humanities

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If f(x)=x+4 and g(x)= x^2-1 , what is (g*f)(x)?

f(x)=x2−2andg(x)=x−3f(x)=x^2-2 and g(x)= x-3 (g∘f)(x)(g@f)(x)

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Explanation:

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$f (x) = x^{2} - 2 and g (x) = x - 3$ $f(x)=x^2-2 and g(x)= x-3$
$(g \circ f) (x)$ $(g@f)(x)$