How do you find the asymptotes for #y=x*ln[e + (1/x)] #? Precalculus Functions Defined and Notation Asymptotes 1 Answer RedRobin9688 Jun 27, 2018 Asymptote at #x=-1/e,0# Explanation: There is an asymptote at #x=0# because at this point the function is undefined as #1/0# is undefined. There is also an asymptote at #e+1/x=0# as the #ln# function is undefined at #0# #e+1/x=0 , ex+1=0 , ex=-1 x=-1/e# Answer link Related questions What is an asymptote? What are some examples of functions with asymptotes? How do asymptotes relate to boundedness? Why do some functions have asymptotes? What are the vertical asymptotes of #f(x) = (2)/(x^2 - 1)#? Is the x-axis an asymptote of #f(x) = x^2#? Where are the vertical asymptotes of #f(x) = tan x#? Where are the vertical asymptotes of #f(x) = cot x#? How do I find the vertical asymptotes of #f(x)=tan2x#? How do I find the vertical asymptotes of #f(x) = tanπx#? See all questions in Asymptotes Impact of this question 3236 views around the world You can reuse this answer Creative Commons License