How do you find the Limit of $ln(n)/ (ln(n))^2$ as n approaches infinity?

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Answer 1 · 2018-06-27T12:20:46

$lim_(n->oo) lnn/(lnn)^2 =0$

$lnn/(lnn)^2 = lnn/(lnn xx lnn)$

$= cancel(lnn)/(cancel(lnn) lnn) = 1/lnn$

$:. lim_(n->oo) lnn/(lnn)^2 = lim_(n->oo) 1/lnn -> 1/oo$

$= 0$

How do you find the Limit of ln(n)/ (ln(n))^2ln(n)/ (ln(n))^2 as n approaches infinity?