Question

How do you solve `|(x/2) + 3| = 3x -3`?

Answer 1

`|(x/2)+3|=3x-3`
`x/2 + 3=+-(3x-3)`
Therefore, `x/2 + 3=(3x-3) or (3-3x)`
When, `x/2 + 3= 3x-3`
`6=(5x)/2`
`12=5x`
`x=12/5`
^1st answer

When, `x/2 +3=3-3x`
`(7x)/2=0`
`7x=0`
`x=0`

Therefore, `x=0 or x= 12/5`