Does the series converge or diverge?

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sum_(n=1)1/(n^(1+1/n)

1 Answer
Jun 28, 2018

It diverges, since it is asymptotically equivalent to 1/n

Explanation:

Let's use the comparison test. It goes like this: if you want to know if a series a_n converges, and

\lim_{n\to\infty}\frac{a_n}{b_n} = c

where both a_n and b_n are sequences with positive terms and c is finite, theny both a_n and b_n converge or diverge.

In this case, since

\lim_{n\to\infty}\frac{1}{n^{1+\frac{1}{n}}} = \frac{1}{n}

we may try to use b_n=1/n as comparison. Ideed, we have

\lim_{n\to\infty}\frac{\frac{1}{n^{1+\frac{1}{n}}}}{1/n} = \lim_{n\to\infty}\frac{n^{-1-1/n}}{n^{-1}}=\lim_{n\to\infty}n^{(-1-1/n)-(-1)}

=\lim_{n\to\infty}n^{-1/n} = 1

So, the two series behave the same. Sine

\sum_{n=1}^\infty 1/n=\infty

then your series diverges as well.