Question

How do you differentiate `f(x)=sqrt((7-2x^3)` using the chain rule.?

Answer 1

`f'(x)=(-3x^2)/sqrt(7-2x^3)`

Explanation:

Chain rule:
`y=f(g(x))->dy/dx=f'(g(x))g'(x)`
`d/dx(sqrt(7-2x^3))=1/(2sqrt(7-2x^3))d/dx(7-2x^3)`
`:.d/dx(sqrt(7-2x^3))=(-3x^2)/sqrt(7-2x^3)`