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Find the heat given out when 10 g of steam at 100 oC condenses and cools to water at 50 oC?

1 Answer

Jun 30, 2018

$24.7 k J$ $24.7kJ$

Explanation:

Specific heat capacity of water $(C) = 4200 J k g^{- 1} K^{- 1}$ $(C)= 4200 J kg^-1 K^-1$

Specific latent heat of evaporation of water $(L) = 2.26 M J k g^{- 1}$ $(L) = 2.26 MJ kg^-1$

$Mass = 10 g = \frac{10}{1000} = 0.01 k g$ $"Mass" = 10g = 10/1000 = 0.01kg$

Energy in condensing $= m L = 0.01 \times 2260000 = 22, 600 J$ $=mL = 0.01 × 2260000 = 22, 600 J$

Energy during cooling $= mCΔθ = 0.01 × 4200 × 50 = 2,100 J$

Total energy given out $= 22, 600 + 2,100 = 24,700 J =24.7kJ$

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