How do you graph 6x>=-1/3y6x≥−13y on the coordinate plane?

1 Answer
Tony B
Jun 30, 2018

See explanation

Explanation:

Given: 6x >= -1/3y6x≥−13y

Multiply both sides by (-1 )

-6x <= 1/3ycolor(white)("dd")−6x≤13ydd Notice that the inequality has turned round.

Multiply both sides by 3

-18x<=y−18x≤y

Now plot the straight line graph of y=-18xy=−18x

Draw any vertical line. yy can and may take on any value above and on y=-18xy=−18x

Example: suppose I pick on x= 1/2x=12 Then the brown line in the graph below represents all the feasible values for yy at x=1/2x=12

Lots and lots of these lines, when combined, give an 'area' on the graph (as shaded) that represents all the possible values of yy for all the possible values of xx.

Tony B

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