The length of a rectangle is $x + 2$ $x+2$ and the width is $x - 6$ $x-6$ . What is the perimeter of this rectangle?

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Answer 1 · 2018-07-01T13:18:54

Perimeter $p = 4 \cdot (x - 2)$ $color(maroon)(p = 4 * (x - 2)$

Perimeter of a rectangle $p = 2 \cdot (l + w)$ $p = 2 * (l + w)$

Given $l = x + 2, w = - 6$ $l = x+2, w = -6$

$p = 2 \cdot (x + 2 + x - 6)$ $p = 2 * (x + 2 + x - 6)$

Perimeter $p = 4 \cdot (x - 2)$ $p = 4 * (x - 2)$

Answer 2 · 2018-07-01T14:15:50

$4 x - 8$ $4x-8$

Perimeter of a rectangle is given by the equation:

$P = 2 (l + w)$ $P=2(l+w)$

where:

$l$ $l$ is the length of the rectangle

$w$ $w$ is the width of the rectangle

So, we get:

$P = 2 (x + 2 + x - 6)$ $P=2(x+2+x-6)$

$= 2 (2 x - 4)$ $=2(2x-4)$

$= 4 x - 8$ $=4x-8$

The length of a rectangle is x+2x+2 and the width is x−6x-6. What is the perimeter of this rectangle?