An isosceles triangle has a base of 20 cm and legs measuring 36 cm. How long are the legs of a similar triangle with base measuring 50 cm?

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An isosceles triangle has a base of 20 cm and legs measuring 36 cm. How long are the legs of a similar triangle with base measuring 50 cm?

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Answer 1 · 2018-07-02T15:12:54

$90$ $90$ centimeters

Explanation:

Because both triangles are similar, we have:

$\frac{b_{1}}{l_{1}} = \frac{b_{2}}{l_{2}}$ $b_1/l_1=b_2/l_2$

where:

$b_{1}, b_{2}$ $b_1,b_2$ are the bases of the first and second triangle, respectively

$l_{1}, l_{2}$ $l_1,l_2$ are the legs of the first and second triangle, respectively

So, we get:

$(20 \ "cm")/(36 \ "cm")=(50 \ "cm")/l_2$

$l_2=(36color(red)cancelcolor(black)"cm")/(20color(red)cancelcolor(black)"cm")*50 \ "cm"$

$=1.8*50 \ "cm"$

$=90 \ "cm"$

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An isosceles triangle has a base of 20 cm and legs measuring 36 cm. How long are the legs of a similar triangle with base measuring 50 cm?

1 Answer

Explanation:

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