How do you solve $2 (a - 3) = 4 a - (2 a - 6)$ $2( a - 3) = 4a - ( 2a - 6)$ ?

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How do you solve $2 (a - 3) = 4 a - (2 a - 6)$ $2( a - 3) = 4a - ( 2a - 6)$ ?

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Answer 1 · 2018-07-02T23:39:12

First, simplify
then solve, remembering PEMDAS(parentheses, exponents, multiply, divide, add, subtract) go in order

Explanation:

$2 (a - 3) = 4 a - (2 a - 6)$ $2(a-3) = 4a-(2a-6)$

$2 a - 6 = 4 a - 2 a + 6$ $2a-6=4a-2a+6$

then you combine like terms

$2 a - 6 = 2 a + 6$ $2a-6 =2a+6$

add six to both sides

$2 a = 2 a + 12$ $2a=2a+12$

since this is not mathematically possible, our equation has no solutions. A given quantity can't be equal to that given quantity plus $12$ $12$ .

Hope this helps!

Answer 2 · 2018-07-03T03:51:29

No solutions

Explanation:

On the left, we can distribute the $2$ $2$ and on the right we can distribute the negative sign. We now have

$2 a - 6 = 4 a - 2 a + 6$ $2a-6=4a-2a+6$

Combining like terms on the right gives us

$2 a - 6 = 2 a + 6$ $2a-6=2a+6$

We cannot subtract six from a value and have it be equal to that value plus $6$ $6$ , because $- 6 \neq 6$ $-6!=6$ .

To further solve this equation, we get

$2 a = 2 a + 12$ $2a=2a+12$

$a = a + 6$ $a=a+6$

$cancela=cancela+6$

$0!=6$

There are no $a$ values that make this equation true.

Hope this helps!

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How do you solve $2 (a - 3) = 4 a - (2 a - 6)$ $2( a - 3) = 4a - ( 2a - 6)$ ?

2 Answers

Explanation:

Explanation:

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