How do you solve the systems of equations $2x+3y=10$ and $3x-10y=15$ ?

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Answer 1 · 2018-07-03T07:17:10

Just arrange the equations. $x=5$ and $y=0$

$2x+3y = 10$
or
$-6x -9y = -30$ (after multiplying -3 (all terms)).

$3x-10y =15$
or
$6x - 20y = 30$ (after multiplying 2 (all terms)).

Add them:
$-6x - 10 y = -30$
$6x - 20y = 30$

$-30y = 0$
$y=0$

Use the first equation to find x:
$2x + 3y = 10$

$2x=10$ (because y is zero)

$x=10/2 = 5$

How do you solve the systems of equations 2x+3y=102x+3y=10 and 3x-10y=153x-10y=15?