How do you calculate the volume of 66.5 g of carbon monoxide at STP?

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Answer 1 · 2018-07-03T14:12:35

#"Volume" = 53.2dm^3#

Well simple comparison method..

#CO rarr STP#

#"Molar mass of" color(white)xCO = 12 + 16 = 28gmol^-1#

Let the volume be represented as #x#

Therefore;

#28gmol^-1 rarr 22.4moldm^-3#

#66.5g rarr xdm^3#

Cross multiplying;

#28 xx x = 22.4 xx 66.5#

#28x = 1489.6#

#x = 1489.6/28#

#x = 53.2dm^3#