How could i solve this?

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How could i solve this?

the equation $f (x) = x^{2}$ $f(x)=x^2$ can be written as $x^{3} + p x^{2} + q = 0$ $x^3+px^2+q=0$
show that p=-1 and q=-20

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Answer 1 · 2018-07-03T14:34:26

Are you sure you have included all details here? Normally if $f (x) = x^{2}$ $f(x)=x^2$ , $f (x) \neq x^{3} + p x^{2} + q$ $f(x)!=x^3+px^2+q$ , so there is something I don't understand here.

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How could i solve this?

the equation $f (x) = x^{2}$ $f(x)=x^2$ can be written as $x^{3} + p x^{2} + q = 0$ $x^3+px^2+q=0$
show that p=-1 and q=-20

1 Answer

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Impact of this question

Science

Math

Humanities

... and beyond

How could i solve this?

the equation f(x)=x2f(x)=x^2 can be written as x3+px2+q=0x^3+px^2+q=0 show that p=-1 and q=-20

1 Answer

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Impact of this question

the equation $f (x) = x^{2}$ $f(x)=x^2$ can be written as $x^{3} + p x^{2} + q = 0$ $x^3+px^2+q=0$
show that p=-1 and q=-20