Determine the amount of water required to produce 500 ml of a solution that is 35% of alcohol dissolved in water?

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Determine the amount of water required to produce 500 ml of a solution that is 35% of alcohol dissolved in water?

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Answer 1 · 2018-07-04T07:25:38

325 mL

Explanation:

$% (v/v) = \frac{volume of solute}{volume of solution} \cdot 100 %$ $%"(v/v)"="volume of solute"/"volume of solution"*100%$

From the question, alcohol is the solute and water is the solvent . Together, they combine to become solution .

Therefore,
$volume of solute = volume of alcohol$ $"volume of solute " = " volume of alcohol"$

$volume of solution = volume of solute + volume in solvent = volume of alcohol + volume of water = 500 mL$ $"volume of solution" = "volume of solute" + "volume in solvent" = "volume of alcohol" + "volume of water" = "500 mL"$

Plug in the given values into the percent volume formula to find the volume of alcohol,
$% (v/v) = \frac{volume of solute}{volume of solution} \cdot 100 %$ $%"(v/v)"="volume of solute"/"volume of solution"*100%$

$35 % = \frac{volume of alcohol}{500 mL} \cdot 100 %$ $35%="volume of alcohol"/"500 mL"*100%$

$volume of alcohol = \frac{35% \cdot 500 mL}{100%} = 175 mL$ $"volume of alcohol" = ("35%"*"500 mL")/"100%"="175 mL"$

From the calculated volume of alcohol, we can now find the volume of water,

$volume of solution = volume of alcohol + volume of water$ $"volume of solution" = "volume of alcohol" + "volume of water"$

$500 mL = 175 mL + volume of water$ $"500 mL" = "175 mL" + "volume of water"$

$volume of water = 500 mL - 175 mL = 325 mL$ $"volume of water" = "500 mL" - "175 mL" = "325 mL"$

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Determine the amount of water required to produce 500 ml of a solution that is 35% of alcohol dissolved in water?

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