Find the average velocity of a car which travels 360 km in 6 hours, show in m/s and km/h ?

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Answer 1 · 2018-07-04T10:03:50

Divide the distance by the time you will get average velocity (or more properly: average speed).

$\frac{360 km}{6 h} = 60 km/h$ $"360 km"/"6 h" = "60 km/h"$

This is equal to $16.7 m/s$ $"16.7 m/s"$ because

$60 km = 60 km \times \frac{1000 meters}{1 km} = 60000 meters$ $"60 km" = "60 km" xx "1000 meters"/"1 km" = "60000 meters"$

$1 hour = 60 min \times \frac{60 seconds}{1 min} = 3600 s$ $"1 hour" = "60 min" xx "60 seconds"/"1 min"= "3600 s"$

So

$60 km/h = \frac{60000 m}{3600 s} = 16.7 m/s$ $"60 km/h" = "60000 m"/"3600 s" = "16.7 m/s"$

Answer 2 · 2018-08-05T12:26:12

Average velocity $v = 60$ $v = 60$ $\frac{k m}{h}, = \frac{50}{3} \frac{m}{s}$ $(km)/h, = 50/3 m / s$

Average velocity (v) = distance travelled (d) / time taken (t).

Given : Distance travelled = 360 km, time taken = 6 hours.

$v = \frac{d}{t} = \frac{360}{6} = 60$ $v = d / t = 360 / 6 = 60$ $\frac{k m}{h}$ $(km)/h$

$1 k m = 1000 m, 1 h o u r = 60 \cdot 60 = 3600 sec$ $1 km = 1000 m, 1 hour = 60 * 60 = 3600 sec$

$:. v = (60 * 1000) / 3600 = 60 * 5/18 = 50/3$ $m / sec$