Question

Given log4=0.6021, log9=0.9542, and log12=1.-792, how do you find log 0.00009?

Answer 1

`log 0.00009 = -4.0458`

Explanation:

`log 0.00009 = log (10^-5 xx 9)`

`= log 10^-5 + log 9`

`= -5 + 0.9542`

`= -4.0458`

Note:

• `log (a xx b) = log a + log b`
• `log_b b^n = n xx log_b b = n`