A ray of light travels from air into a liquid, The ray enters the liquid at an angle of 30.0°. The angle of refraction is 22.0°. Using Snell’s law, calculate the: index of refraction of the liquid. What might the liquid be?

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A ray of light travels from air into a liquid, The ray enters the liquid at an angle of 30.0°. The angle of refraction is 22.0°. Using Snell’s law, calculate the: index of refraction of the liquid. What might the liquid be?

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Answer 1 · 2018-07-03T11:04:38

Here $angle of incidence (i) = 30^{\circ}$ $"angle of incidence" (i)=30^@$

$angle of refraction(r)=22∘$ $"angle of refraction" (r)=22^@$

Then refractive index

$μ = \frac{sin i}{sin r} = \frac{sin 30}{sin 22} = 1.33$ $mu=sini/sinr=sin30/sin22=1.33$

So the liquid is water

Answer 2 · 2018-07-04T14:02:21

The liquid is water $(H_{2} O)$ $(H_2O)$ .

Explanation:

Snell's law states that:

$n_{1} sin i = n_{2} sin r$ $n_1sini=n_2sinr$

where:

$i$ $i$ is the angle of incidence

$r$ $r$ is the angle of refraction

$n_{1}$ $n_1$ is the refractive index of substance $1$ $1$

$n_{2}$ $n_2$ is the refractive index of substance $2$ $2$

For air, the refractive index is $1$ $1$ , and so:

$:.sin30=n_2*sin22$

$n_2=(sin30)/(sin22)$

$~~1.33$

From here, water seems to have a refractive index of $1.33$ , and so this liquid is water.

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A ray of light travels from air into a liquid, The ray enters the liquid at an angle of 30.0°. The angle of refraction is 22.0°. Using Snell’s law, calculate the: index of refraction of the liquid. What might the liquid be?

2 Answers

Explanation:

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