How do you evaluate $(6 \times 10^{3}) \cdot (4.6 \times 10^{5}) \cdot (2 \times 10^{- 2})$ $(6\times 10^ { 3} ) \cdot ( 4.6\times 10^ { 5} ) \cdot ( 2\times 10^ { - 2} )$ ?

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Answer 1 · 2018-07-05T22:27:56

$55.2 \times 10^{6}$ $55.2\times 10^{6}$

Given that

$(6 \times 10^{3}) \cdot (4.6 \times 10^{5}) \cdot (2 \times 10^{- 2})$ $(6\times 10^3)\cdot(4.6\times 10^5)\cdot (2\times 10^{-2})$

$= (6 \times 4.6 \times 2) \times (10^{3} \times 10^{5} \times 10^{- 2})$ $=(6\times 4.6\times 2)\times(10^{3}\times 10^{5}\times 10^{-2})$

$= (55.2) \times (10^{3 + 5 - 2})$ $=(55.2)\times(10^{3+5-2})$

$= 55.2 \times 10^{6}$ $=55.2\times 10^{6}$

Answer 2 · 2018-07-06T10:21:47

$6 \times 4.6 \times 2 = 55.2$ $6xx4.6xx2=55.2$

$10^{3} \times 10^{5} \times 10^{- 2} = 10^{3 + 5 - 2} = 10^{6}$ $10^3xx10^5xx10^-2=10^(3+5-2)=10^6$

Putting these together

$55.2 \times 10^{6} = 5.52 \times 10^{7}$ $55.2xx10^6=5.52xx10^7$

How do you evaluate (6\times 10^ { 3} ) \cdot ( 4.6\times 10^ { 5} ) \cdot ( 2\times 10^ { - 2} )(6×103)⋅(4.6×105)⋅(2×10−2)(6\times 10^ { 3} ) \cdot ( 4.6\times 10^ { 5} ) \cdot ( 2\times 10^ { - 2} )?