How do I standardise scores?
Mean = 90
Standard dev= 2
P(87.2<X<k) = 0.5964
I need to find k.
Mean = 90
Standard dev= 2
P(87.2<X<k) = 0.5964
I need to find k.
1 Answer
Usually normal tables distribution are N(0,1). This is the reason because we normalize. In our case we have
Normalize is equivalent to make a variable change in form
In our case:
Depending on Normal table available these values will be calculated in one way or in other but with same results...
In my case I have a Normal table which gives