How do you evaluate $3 \times \sqrt{5} + 2 \times \sqrt{2}$ $3xxsqrt(5) + 2xxsqrt(2)$ ?

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Answer 1 · 2018-07-10T15:50:03

$9.536$ $9.536$

$3 \times \sqrt{5} + 2 \times \sqrt{2}$ $3 xx sqrt5 + 2 xx sqrt2$

$3 \sqrt{5} + 2 \sqrt{2}$ $3sqrt5 + 2sqrt2$

$\sqrt{5} = 2.236$ $sqrt5 = 2.236$

$\sqrt{2} = 1.414$ $sqrt2 = 1.414$

Substituting..

$3 (2.236) + 2 (1.414)$ $3(2.236) + 2(1.414)$

$6.708 + 2.828$ $6.708 + 2.828$

$9.536$ $9.536$

Answer 2 · 2018-07-10T18:08:05

$3 \times \sqrt{5} + 2 \times \sqrt{2} = 3 \sqrt{5} + 2 \sqrt{2}$ $3xxsqrt5+2xxsqrt2=color(blue)(3sqrt5+2sqrt2$

Given:

$3 \times \sqrt{5} + 2 \times \sqrt{2}$ $3xxsqrt5+2xxsqrt2$

Simplify.

$3 \sqrt{5} + 2 \sqrt{2}$ $3sqrt5+2sqrt2$

This cannot be simplified further since the radicals are not the same and are prime numbers.

How do you evaluate 3xxsqrt(5) + 2xxsqrt(2)3×√5+2×√23xxsqrt(5) + 2xxsqrt(2)?