C) A cylinder contains 0.040 m3 of N2 at a pressure of 2.0 MPa. When the gas is allowed to escape it expands until it reaches atmospheric pressure of 100 KPa. What volume does the gas occupy after expanding?

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Answer 1 · 2018-07-12T18:31:20

$V_{2} = 0.8 m^{3}$ $V_2 = 0.8m^3$

$P_{1} V_{1} = P_{2} V_{2}$ $P_1V_1 = P_2V_2$

$P_{1} = 2.0 M P a = 2 \times 10^{6} P a$ $P_1 = 2.0 MPa = 2×10^6Pa$

$P_{2} = 100 K P a = 100 \times 10^{3} P a$ $P_2 = 100 KPa = 100 xx 10^3Pa$

$V_{1} = 0.040 m^{3}$ $V_1 = 0.040 m^3$

$V_{2} = x m^{3}$ $V_2 = xm^3$

Plugging in the values;

$2 \times 10^{6} \times 0.04 = 100 \times 10^{3} \times x$ $2×10^6 xx 0.04 = 100 xx 10^3 xx x$

$8 \times 10^{4} = 1 \times 10^{5} x$ $8 xx 10^4 = 1 xx 10^5x$

$x = \frac{8 \times 10^{4}}{1 \times 10^{5}}$ $x = (8 xx 10^4)/(1 xx 10^5)$

$x = 0.8$ $x = 0.8$

Therefore;

$V_{2} = 0.8 m^{3}$ $V_2 = 0.8m^3$