What will the change in energy of a capacitor when its voltage is increased by20% a, 22%b, 44%, c33% d 55%?

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Answer 1 · 2018-07-13T10:31:31

$"option b is true."$

$"The energy saved by a capacitor can be calculated using the formula " E=1/2*C V^2$

$"Where C is Capacitance of capacitor and V is Voltage of Capacitor.."$

$E prop V^2$

$"The Energy saved in Capacitor is directly proportional with square of the voltage of Capacitor."$

$"new voltage of capacitor is v+0.2V=1.2V, if voltage increase by 20%."$

$"now, energy saved in capacitor is " E_1 prop(1.2V)^2 prop 1.44V^2$

$"increased energy is 1.44-1=0.44"$

$"rate of increased 0.44/1=0.44 "$

$44 %$