What volume is occupied by 1.5 moles of oxygen, $O_2$ , gas at STP?

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Answer 1 · 2018-07-13T10:29:23

$33.6$ liters

The molar volume of an ideal gas at STP is 22.4 liters/mole

$1.5 xx 22.4 = 33.6$

Answer 2 · 2018-07-13T10:49:57

$"Volume Occupied" = 33.6dm^3$

Let the volume occupied be represented by $x$

Since $1.5$ moles of $O_2$ gas yield $xdm^3$ of $O_2$ gas

Therefore;

$(2 xx 16)gmol^-1$ of $O_2$ gas will produce $22.4dm^3$ of $O_2$ gas

$1$ of $O_2$ gas will produce $22.4dm^3$ of $O_2$ gas

$1.5 -> x$

$1 -> 22.4$

Cross multiplying;

$x xx 1 = 1.5 xx 22.4$

$x = 33.6$

Hence;

$"Volume Occupied" = 33.6dm^3$

What volume is occupied by 1.5 moles of oxygen, O_2O_2, gas at STP?